2w^2+3w+7=4

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Solution for 2w^2+3w+7=4 equation: 



2w^2+3w+7=4

We move all terms to the left:

2w^2+3w+7-(4)=0

We add all the numbers together, and all the variables

2w^2+3w+3=0

a = 2; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·2·3
Δ = -15
Delta is less than zero, so there is no solution for the equation

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